Voltage Dividers Interview Questions 

How do I obtain a value of the voltage across the resistor Re? And how do we go about doing that?

here's what i got:

Mom: pitched in with brother and sister to get her 2 new sets of dishes, and and a sink divider mat
Dad: an all-purpose voltage tester thing and bleacher seat
Katie (sister, age 20): a decall for her car, a fancy checkbook holder, contact case, tape adapter
Kason (brother, 18): $15 itunes giftcard, nice pullover collared dress shirt
Granny/Papa:i painted them a ceramic plate
Gerri (severely mentally handicapped aunt): new baby bottles for her dolls, book of stickers, new notebook to put them in, new fancy hair-thing
All aunt/uncles and grandma/grandpas: picture frame with pic of us 3 kids in it
cousins:
Kersten (16):a glow in the dark basketball hoop
Kameron (14): "Vader Was Framed" t-shirt
Kalvin (10):water balloon launcher

ok, which ones do i need to get more stuff for?. thoughts?

12volt power supply, 100 ohm resistor, 500 ohm resistor. Explain how to obtain 2 lower voltages and work out their values.

Basicly i have been doing everything. I put my FSB to 400 memory divider to 1:1 V core is at 1375 and my ram voltage 1.9. So then i run CPU-Z and nothing changes... what am i doing wrong?

now..someone told me that if u connect 2 resistors in series and their mid point will be divided voltage..or something like that.,
i wanted to know if i can build a potential divider to run a 3 Volt LED with a 12 volt adapter?..and how do i calculate that what amount of resistance i need.to divide the voltages for the LED...or some formula like that?.and how do i calculate that what amount of resistance i need to limit one ampere(or volt)

will a potential divider work as a kind of ...power supply that will divide 12 V into 7V and 5V ,?

we have to make a sensor on our own for our physics coursework. the teacher gave us loads of ideas and i chose (now i'm wondering why i chose it) a concentration sensor. I decided to use CuSO4 as my salt whose concentration i'd measure using the sensor. I need to use a potential divider and a voltmeter in my sensor. what formulas would i need for calculating concentration of a salt from current, voltage and resistance? and how could i set my sensor up? any ideas at all as to any websites on sensors or anything helpful will be appreciated.

I know that resistors oppose the flow of current, so why dont they also lower voltage since current is proportional to voltage? why is there a high voltage when resistance is high as in potential divider?

I'm stuck on a few problems for physics! If you could help at all that would be greatly appreciated!!

1. A 20-ohm lamp and a 5-ohm lamp are connected in series and placed across a potential difference of 50 volts. What is:
a) the equivalent resistance of the circuit?
b) the current in the circuit?
c) the voltage drop across each lamp?
d) the power dissipated in each lamp?

2. A 16-ohm and a 20-ohm resistor are connected in parallel. A difference in potential of 40 volts is applied to the combination.
a) Compute the equivalent resistance of the parallel circuit.
b) What is the current in the circuit?
c) How large is the current through the 16-ohm resistor?

3. Pete is designing a voltage divider using a 12-volt battery and a 100-ohm resistor as R.b. What resistor should be used as R.a. if the output voltage across R.b. is to be 4 volts?

please explain the designing of v d b circuit with an example

if you can provide a schematic diagram much better. given, if the voltage is 12000 and i want the volt ohm meter to read only 12 volts. and i can only use resistors,capacitors and diodes. using voltage divider with a ratio of 1000 to 1.

hey can u help me this? if u can provide a sketch much better. tnx!!

when the opamp is used as a buffer,it nullifies the loading effect of the external circuit, like when using i checked the potential dividers voltage across one of the two equal resistors,for voltage=5V,my multimeter showed 2.2V when it should have been 2.5V.But when i connected the p.d. to the buffer opamp and then measured the o/p,it was 2.5 V.
Now i know what a buffer is and all that,but i didn't understand how it helps in nullifying the output.Though its not in my syllabus,i just wanted to get to the concept.

I am an idiot. I can't calculate the cutoff frequency. Where am I going wrong?

Simple Lowpass filter, like on Fig 1 of wiki page for LPF.

G = Zc / ( R + Zc ) = 0.5^0.5
--Voltage Divider, G=sqroot of 1/2

= 1 / ( R / Zc + 1)
--Divide num&denom by Zc

Zc = 1/(j*w*C)
--impedance of a cap

1/(jwRC + 1) = 0.5^0.5

1/(0.5^0.5) = jwRC + 1

There is an error. The answer for w should be w = 1 / (R*C)
Where did the 'j' go? (imaginary part)? I am loosing my mind maybe

w = (2^0.5 - 1) / (j * T) where T=R*C

Please help!

I'm trying use a 12 volt, 300mA plug-in power supply (from an old scanner) for my vintage pachinko machine. I just need 3 volts (for the EL wire), 4.5 volts (for LEDs,sound box), and 12 volts ( for wireless triggers). I made a voltage divider with resistors, connected it to the power supply, but my voltmeter keeps showing a constant 12 volts. What am I doing wrong?
I don't have any capacitors or diodes connected.
Thank you for your help.

I don't want someone to design it for me, but to show me how to design it. There are a few specs that we have to follow, in order of importance:
gain = -20
Rc = 10k ohms
Input resistance > 10k ohms
low cutoff frequency = 50 Hz
10 Vpp without distortion

I have to use a voltage divider bias, on a common emitter amp. I have the option of using any number of resistors...

I am having a really tough time with this, I have already put in 6 hours and cannot figure it out. Any help would be greatly appreciated.

I have 48 VDC source.. then i am using voltage divider ( 10 ohm and 70 ohm). At 10 ohm side, after i do some calculating, i have 6 VDC with 0.6 A. From this 6 VDC, i input it to a 7805 regulator. the result is i have a 5 VDC power supply. Is it safe if i make this kind of circuit? will my resistor or 7805 being burn out? power consumption of the load is not very high.. just running some LED and relay.. Thx alot..